| James Charles Byrnes, Julia Richman, John Storm Roberts - 1911 - 260 páginas
...dividend by a vertical line or a decimal point as many figures as there are ciphers in the divisor ; then divide the remaining figures of the dividend by the remaining figures of the divisor. 3. To divide by 50, multiply the dividend by 2 and divide by 100 by pointing off two places from the... | |
| James Charles Byrnes, Julia Richman, John Storm Roberts - 1914 - 264 páginas
...dividend by a vertical line or a decimal point as many figures as there are ciphers in the divisor; then divide the remaining figures of the dividend by the remaining figures of the divisor. 3. To divide by 50, multiply the dividend by 2 and divide by 100 by pointing off two places from the... | |
| James A. Lyons - 1912 - 392 páginas
...the same number 9 | 00)342 | 16 of figures from the right of the 38 QUOTIENT. 16 REMAINDER. dividend. Divide the remaining figures of the dividend by the remaining figures of the divisor. To the remainder, if any, annex the figures cut off from the dividend. 58. Proving Division. Division... | |
| John Henry Walsh - 1919 - 512 páginas
...terminal cipher or ciphers in the divisor and the same number of figures from the right of the dividend. Divide the remaining figures of the dividend by the remaining figures of the divisor. Write as the remainder the figures of the dividend that have been cut off, prefixing the partial remainder,... | |
| 1915 - 902 páginas
...the ciphers from the right of the divisor, and as many figures from the right of the dividend. II. Divide the remaining figures of the dividend by the remaining figures of the divisor, for the final quotient. III. Prefix the remainder to the figtires cut off, and the result will be the... | |
| Joseph Ray - 1866 - 210 páginas
...right of the divisor, cut them off, and the same number of figures from the right of the dividend, divide the remaining figures of the dividend by the remaining figures of the divisor; to the remainder, if any, annex the figures cut off, which will form the true remainder. 25. 24725H-... | |
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