| Henry Major - 1873 - 588 páginas
...is the angle ABC greater than ACB. XTX. — The greater angle of every triangle is subtended bit fhe greater side, or has the greater side opposite to it. Let ABC be a triangle, of which the angle ABC is greater than the angle BCA ; the side AC is likewise greater than the side AB. For, if it be... | |
| Edward Atkins - 1874 - 426 páginas
...angle ACB. GEOMETRY. Z1VABC > ^ BCAAC not = AB AC not < Make ^ = AC^ |CD> .-.DB>BC. Proposition 19. — Theorem. The greater angle of every triangle is subtended...opposite to it. Let ABC be a triangle, of which the angle ABC is greater than the angle BCA; The side AC shall be greater than the side AB. PROOF.— If AC be... | |
| Euclides - 1874 - 342 páginas
...The angle ABC is greater than the angle ACB. Therefore the greater side, &c. QED PROPOSITION 19.— Theorem. The greater angle of every triangle is subtended...opposite to it. Let ABC be a triangle of which the angle ABC is greater than the angle BCA. Then the side AC shall be greater than the side AB. A. For, if AC... | |
| Euclides - 1874 - 120 páginas
...proposition by producing the lea side AB to E, making AE equal to AC, and joining CE. PROPOSITION 19. THEOREM. The greater angle of every triangle is subtended...greater side, or has the greater side opposite to it. i Let ABC be a triangle, of which the angle ABC ' • is greater than the angle ACB : the side AC is... | |
| Edward Atkins - 1876 - 130 páginas
...the angle ABC greater than the angle ACB. Therefore, the greater side, £e. QED Proposition 19.— Theorem. The greater angle of every triangle is subtended...greater side, or has the' greater side opposite to it. ^"A"IC >• Let ABC be a triangle, of which the angle ABC is greater * UCA. fkun t]10 angie BCA; The... | |
| Education Department,London - 1876 - 1010 páginas
...; CD is drawn to any point D of the side Ab. Show that CD is greater than CA, but less than CB. 2. The greater angle of every triangle is subtended by the greater side. If two right angled isosceles triangles have their bases equal, they will be equal in all respects.... | |
| Edward Atkins - 1877 - 72 páginas
...the greater side, &c. QE D, AC > AB. / BCD, Mid / ADB = I ABD and . i ABD >i BCD. Proposition 19. — Theorem. The greater angle of every triangle is subtended...greater side, or has the greater side opposite to it. ^'VAUC' -» Let ABC be a triangle, of which the angle ABC is greater - *CA' than the angle BCA; The... | |
| Moffatt and Paige - 1879 - 428 páginas
...the angle ABC greater than the angle AC B. Therefore, the greater side of every triangle, etc. QED Proposition XIX. Theorem. The greater angle of every...opposite to it. Let ABC be a triangle, of which the angle ABC is greater than the angle BC A. Then the side AC shall be greater than the side A B. For, if AC... | |
| Euclides - 1879 - 146 páginas
...is greater than Z. DCB ; much more is L ABC greater than L ACB. Therefore, the greater side, &c. QED PROPOSITION XIX. THEOREM. The greater angle of every...has the greater side opposite to it. Let ABC be A of which Z. ABC is greater than Then AC is greater than AB. Dem. For if AC be not greater than AB,... | |
| W J. Dickinson - 1879 - 44 páginas
...of a triangle. Prove that the greater side of every triangle is opposite to the greater angle. 19-. The greater angle of every triangle is subtended by...greater side, or has the greater side opposite to it. Same proposition. Hence show that the perpendicular is the shortest straight line that can be drawn... | |
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