 | Henry Martyn Taylor - 1893 - 486 páginas
...the square on the part produced. PROPOSITION 12. In an obtuse-angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side opposite the obtuse angle is greater than the sum of the srjuares on tlte other sides, by twice tite... | |
 | Great Britain. Education Department. Department of Science and Art - 1894 - 894 páginas
...quantity to each of its terms. B. 27. Show that in an obtuse angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite...triangle, between the perpendicular and the obtuse angle. In a triangle ABC the perpendicular from A to BC produced meets it at a point D, such that CD equals... | |
 | Henry Martyn Taylor - 1895 - 708 páginas
...the square on the part produced. PROPOSITION 12. In an obtuse-angled triangle, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side opposite the obtuse angle is greater than the sum of tJie squares on the other sides, by twice the... | |
 | Great Britain. Education Department. Department of Science and Art - 1899 - 348 páginas
...from one of the acute angles of an obtuse-angled triangle to the opposite side produced ; show that the square on the side subtending the obtuse angle...perpendicular falls, and the straight line intercepted between the perpendicular and the obtuse angle. Show that the sum of the squares of the diagonals of... | |
 | 1899 - 824 páginas
...the problem may have a solution. 3. In obtuse-angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced,...side subtending the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle, bv twice the rectangle contained by the... | |
 | Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 330 páginas
...in medial section at A. PROPOSITION 12. THEOREM. In an obtuse.angled triangle, if a perpendicular is drawn from either of the acute angles to the opposite...side subtending the obtuse angle is greater than the sum of the squares on the sides containing the obtuse angle, by twice the rectangle contained by the... | |
 | 1900 - 898 páginas
...AC, and CN ie drawn perpendicular to AB, show that BC1 = 2AB . BN. 7. G. In an obtuse-angled triangle the square on the side subtending the obtuse angle is greater than the sum of the squares on the other two sides by twice the rectangle contained by either of these sides,... | |
 | 1901 - 488 páginas
...In an obtuse-angled triangle, the square on the side subtending the obtuse angle exceeds the sum of the squares on the sides containing the obtuse angle, by twice the rectangle contained by either of them, and its continuation to meet a perpendicular on it from the opposite angle. 4. Prove... | |
 | 1903 - 188 páginas
...SINCLAIR SCHOLARSHIP EXAMINATION. I. (a) Shew that in an obtuse-angled triangle, if a perpendicular is drawn from either of the acute angles to the opposite...on the sides containing the obtuse angle, by twice a certain rectangle. (ft) Shew that, if from any point outside a circle, a tangent and a secant be... | |
 | 1903 - 898 páginas
...these points within 1 per cent. Or, 2A. Show that in an obtuse-angled triangle if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side opposite the obtuse angle is greater than the sum of the squares on the sides forming the obtuse angle... | |
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In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle, is greater than the squares on the sides containing the obtuse angle, by twice the... 
