...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 503 = 40*+ 30s. [Fig. 8.] 16. Hence, to find the different sides,...

...circumference of the screw; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) the square of the hypothenuse is equal to the sum of the squares of the base and perpen-dicular ; that is * 2 — A 2 + c 2 ; and extracting the square root...

...circumference of the screw ; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; that is *' = A2 + c2 ; and extracting the square root of these...

...others ; for the three figures will be proportional to the squares of their homologous sides ; now the square of the hypothenuse is equal to the sum of the squares of the two other sides ; therefore, &c. THEOREM. 223. The parts of two chords which cut each...

...and the side B, C, 12 feet. What is the length of the side A, B? a In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the...

...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 50" = 40" + 30!. [Fig. 8.] 16. Hence, to find the different sides,...

...perpendicular 48 rods, how many acres ? Ans. 7a. 2r. 36 rods. ART. 2. — In every right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the other two sides. 1. Hence, when the legs are given, to find the hypothenuse. RULE. Add...

...heart, the circulation of the blood, and the process of respira10. Prove that in a right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the sides. 11 Prove that if two straight lines intersect one another in a circle, the rectangles...

...Humeist did not really doubt that Caesar once lived in Rome — that the sun will rise to-morrow — that the square of the hypothenuse is equal to the sum of the squares of the opposite sides. In all these matters man is satisfied to act upon the knowledge arising...

...Consequently CDML -f LMEA = square ACED = square AFGB -j- BCKH. That is, in every right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the other two sides. This is called the proposition of Pythagoras, because he first discovered...