 | Northwest Territories Council of Public Instruction - 1897 - 628 páginas
...drawn (i) with no pair parallel ; (ii) with one pair parallel ; (iii) with two pairs parallel. (J) Prove that parallelograms on the same base and between the same parallels are equal in area. I. 35. (f) Point out the uses of proposition (I) in mensuration. (d) Prove that if a square and a rhombus... | |
 | 1897 - 154 páginas
...biographical sketch of Haydn. SINCLAIR SCHOLARSHIP EXAMINATION, 1896. MATHEMATICS. 1 Shew that triangles on the same base and between the same parallels are equal in area ; and equal triangles on the same base are between the same parallels. Shew that the straight line... | |
 | Alfred John Pearce - 1897 - 202 páginas
...parallelogram, the length and perpendicular height being given. , Let ABCD be an oblique parallelogram. Now, parallelograms on the same base and between the same parallels are equal (Euc. I. 35). Therefore the area of the oblique parallelogram ABCD equals the area of the rectangle... | |
 | Great Britain. Education Department. Department of Science and Art - 1899 - 348 páginas
...figure equals seven-eighths of two right angles, find the number of sides. (12.) 10. Show that triangles on the same base and between the same parallels are equal in area. ABCD is a parallelogram, and P is a point within the angle formed by DC and the prolongation of AD;... | |
 | Seymour Eaton - 1899 - 362 páginas
...therefor' the triangle ABC is equal to the triangle BCD (Proposition 4). PROPOSITION 35. THEOREM 323 Parallelograms on the same base and between the same parallels are equal to one another. Let the parallelograms ABCD, EBCF be on the same base BC, and between the same parallels... | |
 | American Association for the Advancement of Science - 1899 - 646 páginas
...geometry, and in the third part a strict treatment of equivalence. Even Euclid, in proving his I. 35, " Parallelograms on the same base, and between the same parallels, are equal to one another," does not show that the parallelograms can be divided into pairs of pieces admitting... | |
 | American Association for the Advancement of Science - 1899 - 650 páginas
...geometry, and in the third part a strict treatment of equivalence. Even Euclid, in proving his I. 35, "Parallelograms on the same base, and between the same parallels, are equal to one another," does notshowthat the parallelograms can be divided into pairs of pieces admitting... | |
 | Great Britain. Parliament. House of Commons - 1900 - 686 páginas
...equations (i-) ^ + f (ii.) 2* = 3y \. x + y = a ) I-.- Simplify ax - 4i/2 y - x 8. A resolution was carried by a majority of 9 ; but if onesixth of those who...cent. Consols when £5,230 stock can be bought for £4,975 Os. 9A : find also the income obtained. 13. In a certain examination every candidate took either... | |
 | Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 330 páginas
...recognized system should be allowed, such, for example, as that given on page 11.] PROPOSITION 35. THEOREM. Parallelograms on the same base, and between the same parallels, are equal in area. DE FADEFAEDF Let the parallelograms ABCD, EBCF be on the same base BC, and between the same parallels... | |
 | Manitoba. Department of Education - 1900 - 558 páginas
...within the other, the perimeter of the inner figure will be the smaller. 4. Define a parallelogram. Parallelograms on the same base and between the same parallels are equal. 5. If a parallelogram and a triangle be on the same base and between the same parallels the parallelogram... | |
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Prove that parallelograms on the same base and between the same parallels are equal in area. 
