| Whiting Griswold - 1866 - 144 páginas
...triangle by its sides. RULE 8. From half the sum of the three sides subtract each side separately ; then multiply the half sum and the three remainders continually...together, and the square root of the product will equal the area. RULE 4. Multiply the perpendicular height by the length, equal the area. To find the... | |
| Harris & Brother (Philadelphia) - 1866 - 110 páginas
...sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area. 4. TRAPEZOID — the sum of the two parallel sides X by half the perpendicular height. 5. CIRCLE =... | |
| A. C. Smeaton - 1867 - 314 páginas
...from half the sum subtract each side separately ; then multiply the half sum and the three remainders together, and the square root of the product will be the area required. Let the sides of a triangle be 30, 40, and 50 feet, respectively, what will be the area ? 30 + 40 +... | |
| Benjamin Greenleaf - 1868 - 340 páginas
...area of a TRIANGLE, the three sides being given. side ; multiply the half sum and the three remainders together, and the square root of the product will be the area required. For, let ABC be a triangle whose three sides, AB, BC, AC, are given, but not the altitude CD, and let... | |
| Anthony Nesbit - 1870 - 578 páginas
...area may be found as fol. Iowa : From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area required. This method is too prolix, except in particular cases; the... | |
| Benjamin Greenleaf - 1873 - 202 páginas
...half the sum of the three sides subtract each side ; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 1. Required the area of the triangle ABC, whose base, BC, is 210, and altitude, AD, is 190 feet. 210... | |
| Benjamin Greenleaf - 1874 - 206 páginas
...half the sum of the three sides subtract each side ; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 1. Required the area of the triangle ABC, whose base, BC, is 210, and altitude, AD, is 190 feet. 210... | |
| Lorenzo Fairbanks - 1875 - 472 páginas
...sides are given. RULE. — From half the sum of the three sides subtract each side separately. Then multiply the half sum and the three remainders continually...together, and the square root of the product will he the area. EXAMPLES. 1. Required the area of a triangle whose three sides are, respectively, 24,... | |
| Samuel Mecutchen, George Mornton Sayre - 1877 - 200 páginas
...sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. Note. — When the base and altitude are given, the area is equal to the base multiplied by half the... | |
| Thomas Hunter - 1878 - 142 páginas
...sides only are given. EULE. — From half the sum of the three sides subtract each side sepa~ rately : multiply the half sum and the three remainders continually...square root of the product will be the area required.* • Demonstration.—Let AC=c, CB=<7, and AB=6; and c»—d'=AD a —DB» (e+d) (f—d)=(AD+DB) (AD—DB);... | |
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