 | Emerson Elbridge White - 1870 - 350 páginas
...altitude. 4. To find the area of any quadrilateral having two sides parallel, Multiply one half of the sum of the two parallel sides by the perpendicular distance between tiiem. 5. To find the circumference of a circle, 1. Multiply the diameter by 3.1416. Or, 2. Divide... | |
 | J Alfred Skertchly - 1873 - 184 páginas
...its sides parallel, such as OPWC, is called a trapezoid; and its area is found by multiplying half the sum of the two parallel sides by the perpendicular distance between them. Here the area of 0 PWC equals | (O P+CW) x O C. The ordinate OP denotes the initial velocity, and C... | |
 | Emerson Elbridge White - 1870 - 348 páginas
...altitude. 4. To find the area of any quadrilateral having two sides parallel, Multiply one half of the sum of the two parallel sides by the perpendicular distance between them. 5. To find the circumference of a circle, 1. Multiply the diameter by 3.1416. Or, 2. Divide the area... | |
 | William John Macquorn Rankine, Edward Fisher Bamber - 1873 - 372 páginas
...by a pair of parallel straight lines, and a pair of straight lines not parallel). Multiply the half sum of the two parallel sides by the perpendicular distance between them. 32. Triangle. Rule A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
 | William John Macquorn Rankine, Edward Fisher Bamber - 1873 - 368 páginas
...by a pair of parallel straight lines, and a pair of straight lines not parallel). Multiply the half sum of the two parallel sides by the perpendicular distance between them. 32. Triangle. Rule A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
 | 1874 - 1186 páginas
...juid divided by 2, will be the area of the trapezium. To find the area of a trapezoid. — RULE 1. — Multiply the sum of the two parallel sides by the...between them, and half the product will be the area. RULE 2. — Draw a diagonal, to divide the trapezoid into two triangles ; find the areas of those triangles... | |
 | Thomas Hunter - 1878 - 142 páginas
...feet. Ans. 222^ yards. PROBLEM VT. To find the area of a trapezoid. RULE.—Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.* 1. The parallel sides of a trapezoid are 750 and 1225, and the perpendicular distance between them... | |
 | Moffatt and Paige - 1879 - 506 páginas
...the Area of a Trapezoid. A trapezoid is a quadrilateral figure having two only of its sides parallel. Rule. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and take half the product for the. area. C __ A D f - E --- B Proof. — Let ACDB be a trapezoid, having... | |
 | T. W. Stone - 1881 - 126 páginas
...right-angled parallelogram. Multiply one side, the larger, by the less. The trapezoid. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. The triangle. Multiply the base by the perpendicular, and half the product is the area.... | |
 | Joseph Bateman - 1882 - 576 páginas
...number of feet and inches. For a Trapezoid (two of the sides parallel, but not equal).—Multiply half the sum of the two parallel sides by the perpendicular distance between them. For a Trape.zinm (four straight sides of different lengths).—Obtain a diagonal, by measuring from... | |
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Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 
