 | Nathan Daboll, David Austin Daboll - 1849 - 260 páginas
...CASE n. • ' The first term, last term, and number of terms given, to f,nd the common difference. RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. EXAMPLES. 1. A man bought 17 yards of cloth in arithmetical... | |
 | James Bates Thomson - 1849 - 438 páginas
...12 hours? 604. To find the common difference, when the extremes and the number of terms are given. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference required. OBS. The truth of this rule is manifest from... | |
 | George Roberts Perkins - 1849 - 344 páginas
...the first term, the last term, and the number of terms, to find the common difference, we have this RULE, Divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1. The first term of an arithmetical progression is 5, the last term is 176, and the... | |
 | Benjamin Greenleaf - 1849 - 336 páginas
...quotient will be the common difference. Thus, 27-:-9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
 | Charles Guilford Burnham - 1850 - 350 páginas
...238. — When the extremes and number of terms are given, to find the common difference, we have this RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. 7. If the first term of a series be 3, the last term... | |
 | George Roberts Perkins - 1850 - 356 páginas
...the first term, the last term, and the number of terms, to find the common difference, we have this RULE. Divide the difference of the extremes by the number of terms, less one. EXAMPLES. 1 . The first term of an arithmetical progression is 5, the last term is 176, and the... | |
 | Benjamin Greenleaf - 1850 - 368 páginas
...differences, the quotient will be the common difference. Thus 16 -5- 8 = 2 is the common difference. RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. 1. The extremes are 3 and 45, and the number of terms... | |
 | Roswell Chamberlain Smith - 1850 - 314 páginas
...•*- 5= 5 years, the common difference. A. 5 years. 1 1 . Hence, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will oe the common difference. 12. If the extremes be 3 and 23, and the number of... | |
 | Daniel Leach - 1851 - 280 páginas
...found. 312. To find the common difference when the two extremes and the number of terms are. known,-— RULE. Divide the difference of the extremes by the number of \ terms , less one , and the quotient will be the common difference. This rule may be represented by the formula,... | |
 | Benjamin Greenleaf - 1851 - 332 páginas
...quotient will be the common difference. Thus, 27 -fr- 9 = 3, the common difference. Hence the following RULE. — Divide the difference of the extremes by the number of terms less one, and the quotient is the common difference. • EXAMPLES FOR PRACTICE. 1. The extremes of a series... | |
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Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 
