 | Thomas Keith - 1817 - 306 páginas
...are contained therein? ' , Ant. 92'348l6 feet. PROBLEM IX. To fold the Solidity of a Wedge. ROLE*'. To twice the length of the base, add the length of the edge; multiply the sum by the breadth * Dtmmttrattm. Let AB CD x F represent a wedge : now, when the length... | |
 | William Hawney - 1820 - 336 páginas
...angled parallelogram for its base, and two of its sides meeting in an edge. To find the Solidity. RULE. To twice the length of the base add the length of the edge, multiply the sum by the breadth of the base, and that product by the perpendicular height of the wedge... | |
 | Anthony Nesbit - 1824 - 476 páginas
...that name until the fifteenth century. PROBLEM IX. Tojind the solidity of a cuneus or wedge. RULE. To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge... | |
 | Ireland commissioners of nat. educ - 1834 - 370 páginas
...perpendicular to the plane AC, the wedge is of the common kind ; CG is its edge, and ARBO its back. RULE II. To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and the product by the height of the wedge, and -| of... | |
 | Adrien Marie Legendre - 1836 - 394 páginas
...perpendicular distance between its bases. , PROBLEM VII. To find the solidity of a wedge. RULE. — To twice the length of the base add the length of the edge. Multiply this sum by the breadth of the base, and then by the altitude of the wedge, and take one-sixth... | |
 | Commissioners of National Education in Ireland - 1837 - 290 páginas
...perpendicular to the plane AC, the wedge is of the common kind ; CG is its edge, and ARBO to beck. RULE II. To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and the product by the height of the wedge, and ^ of the... | |
 | Thomas Holliday - 1838 - 404 páginas
...breadth of the base, perpendicular height, and the length of the edge, for the solidity. Rule.—To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge,... | |
 | William Templeton (engineer.) - 1845 - 210 páginas
...95-8188 cubic feet, and x 6-232 = 597-1427 gallons. To find the solid contents of a wedge. Rule. — To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by the perpendicular height from the base, and one-sixth... | |
 | James Robinson (of Boston.) - 1847 - 304 páginas
...we live, supposing the diameter to be 7912 miles? Al't. 987". To FIND THE SOLIDITY OF A WEDGE. RULE. To twice the length of the base add the length of the edge; multiply the sum by the breadth of the base, and the product by one sixth of the perpendicular from... | |
 | 1847 - 190 páginas
...depth = 95-8l88 cubic feet, and X 6-232 = 597-1427 gallonsTo Jind the solid contents of a wedgeRule — To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by the perpendicular height from the base, and one... | |
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To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by one-sixth of the height. 
